Y=-5.3x^2+3.6x+2

Solution for Y=-5.3x^2+3.6x+2 equation:

=-5.3Y^2+3.6Y+2

We move all terms to the left:

-(-5.3Y^2+3.6Y+2)=0

We get rid of parentheses

5.3Y^2-3.6Y-2=0

a = 5.3; b = -3.6; c = -2;
Δ = b2-4ac
Δ = -3.62-4·5.3·(-2)
Δ = 55.36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3.6)-\sqrt{55.36}}{2*5.3}=\frac{3.6-\sqrt{55.36}}{10.6}
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3.6)+\sqrt{55.36}}{2*5.3}=\frac{3.6+\sqrt{55.36}}{10.6}
$